This is the most confusing color post I have ever read. I was so confused I had to reexplain it to myself.
Usually, a stallion is advertised as ‘homozygous black’, He would be EE. If his color is black he is aa too. All offspring will be E_…no chestnuts(e) possible. So saying homozygous black means no chestnuts foals…it doesn’t mean you will produce blacks…the mares genotype will determine if there can be black or bay, but even if the mare is chestnut (ee) she will never have chestnut foals bred to a homozygous black stallion. A chestnut always is ee. The homozygous black stallion has no e to contribute. Many people…like the Holsteiner Verband dislike chestnuts…this is how you prevent chestnut offspring.
If they said he was a homozygous bay(AA) then you know that even if he looks black he is in fact a dark bay. A means black will be in the bay pattern…a means the balck will be all over…A is dominant over a…so bay pattern is dominant over black all over. All his foals will get A_ and will be some shade of bay. He can also be AA EE (homozygous bay AND homozygous black)but you will not see that expressed all the foals will be bay because A is dominant, because he only passes E none of the foals will be chestnut regardless of the mares phenotype.
Ee says whether there is black to modify…E black…e no black.
Aa says what happens to the black…A bay pattern…a black all over
Now…grey…changes any color to white over time. Grey is also dominant over non-grey. A homozygous grey will make all offspring grey eventually. Their base color is still there but it is modified by the grey gene if it is present. A heterozygous grey will have 50% greying foals and 50% non-greying foals.
I just bought a heterozygous grey stallion. We don’t know his genotype but we can use the evidence of his offspring to determine his genotype.
Laird is grey.
Laird has non-greyed offspring so he is heterozygous for the greying gene…50% chance a foal will be greying.
I don’t know the color Laird was foaled as.
Of the foals Laird has had(~20) none of them are chestnut…none of them are black. However, we have some grey offspring and we don’t know what color they greyed from.
20 is not a very large sample. It could be that like the Holsteiner Verband most of the dams he was bred to are bay or black…or greying.
If there was ONE chestnut offspring we would know Laird is heterzygous for the red gene Ee and can pass either E_ or e_
If there was ONE black we would know he is heterozygous for the bay pattern gene Aa passing either A_ or a_
As it stands with the evidence we have he is for sure Gg A_E_ and evidence to hand says Gg AA EE a black offspring would change the AA to Aa and a chestnut offspring would change the EE to Ee.
PatO